y-3/y^2-3y

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Solution for y-3/y^2-3y equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(3*y)-(3/(y^2)) = 0

y-3*y-3*y^-2 = 0

-2*y-3*y^-2 = 0

-y*(3*y^-3+2) = 0

3*y^-3 = -2 // : 3

y^-3 = -2/3

-3 < 0

1/(y^3) = -2/3 // * y^3

1 = -2/3*y^3 // : -2/3

-3/2 = y^3

y^3 = -3/2 // ^ 1/3

y = -(3/2)^(1/3)

-y = 0

-1*y = 0 // : -1

y = 0

y in { 0} 

y = -(3/2)^(1/3)

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